Asked by King
A rectangular water tank measures 2.4m long, 2m wide and 1.5m high. The tank contained some water up to a height of 0.45m
(a) calculate the amount of water, in litres, needed to fill up the tank.
vol = 2.4*2* 1.5- 2.4*2*0.45
=7.2 - 2.16
= 5.04*1000
= 5040L
(b) An inlet pipe was opened and water let to flow into the tank at a rate of 10 litres per minute. After one hour, a drain pipe was opened and water allowed to flow out of the tank at a rate of 4 litres per minute.
(i) the height of water in the tank after 3hours
(ii) the total time taken to fill up the tank
(a) calculate the amount of water, in litres, needed to fill up the tank.
vol = 2.4*2* 1.5- 2.4*2*0.45
=7.2 - 2.16
= 5.04*1000
= 5040L
(b) An inlet pipe was opened and water let to flow into the tank at a rate of 10 litres per minute. After one hour, a drain pipe was opened and water allowed to flow out of the tank at a rate of 4 litres per minute.
(i) the height of water in the tank after 3hours
(ii) the total time taken to fill up the tank
Answers
Answered by
oobleck
empty space volume is 2.4*2*(1.5-0.45) = 5.04 m^3 = 5040L
you are correct
So, initially, there were 2.16 m^3 = 2160L in the tank
during the first hour, 10L/min * 60min = 600L flowed into the tank.
when the valve was opened, the net fill rate was 10-4 = 6L/min
volume after 3 hours was 600 + 6*2*60 L
total minutes to fill was 60 + (5040-600)/6 minutes
you are correct
So, initially, there were 2.16 m^3 = 2160L in the tank
during the first hour, 10L/min * 60min = 600L flowed into the tank.
when the valve was opened, the net fill rate was 10-4 = 6L/min
volume after 3 hours was 600 + 6*2*60 L
total minutes to fill was 60 + (5040-600)/6 minutes
Answered by
Ann kandy
0.68m
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