Asked by Clifford

A rectangular water tank is being filled at a constant rate of 101t/s.The base of the tank has width,w=10m and length,l=15m. If the volume of the tank is given by v=w*l*h where h represents the height of the tank,what is the rate of the height of water in the tank?
Answered by oobleck
not sure what "101t/s" is supposed to mean. If that's tons/second, then you will have to figure the volume per ton. I'll give you a sample calculation.

h = v/(lw) = v/150
so if v is increasing by 101 m^3/s, h is increasing by 101/150 m/s
Answered by bana coco
A rectangular water tank is being filled at the constant rate of 35lt/s. The base of the tank has width,w= 3m and length,l= 5m. If the volume of the tank is given by V=w×l×h where h representsthe height of the tank, what is the rate of change of the height of water in the tank?.
Answered by Sheldon
can this be calculated further
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