To find out how far Lacy runs on Saturday, we first need to calculate how far she runs on Thursday, which is given as 5 1/4 km.
Let's convert 5 1/4 km into an improper fraction:
\[ 5 \frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{20 + 1}{4} = \frac{21}{4} \text{ km} \]
Now, we need to calculate 1 1/2 times this distance for Saturday:
First, we express 1 1/2 as an improper fraction: \[ 1 \frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2} \]
Now, multiply the distance Lacy ran on Thursday by 1 1/2: \[ \text{Distance on Saturday} = \frac{3}{2} \times \frac{21}{4} \]
To multiply these fractions, multiply the numerators and the denominators: \[ \text{Distance on Saturday} = \frac{3 \times 21}{2 \times 4} = \frac{63}{8} \text{ km} \]
Next, we convert \(\frac{63}{8}\) into a mixed number. We divide 63 by 8: \[ 63 \div 8 = 7 \quad \text{(whole number)} \quad \text{with a remainder of } 7 \]
Thus, we write this as: \[ \frac{63}{8} = 7 \frac{7}{8} \]
Hence, Lacy runs \(7 \frac{7}{8}\) km on Saturday.
The final answer is: \[ \boxed{7 \frac{7}{8}} \]