Asked by roman

Though Pat's dog runs 2m/sec slower than Pat, the dog runs three times as fast as Lee. If Lee runs at x m/sec, and Pat races Lee,then, after 10 seconds, Pat will be ??? m ahead of Lee.
Answered by Steve
d = p-2
d = 3x

p-2 = 3x
p = 3x+2

So, after 10 seconds,
Lee has run 10x meters
Pat has run 10(3x+2) = 30x+20

So, Pat is 20x+20 meters ahead of Lee
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