Question

Find three consecutive intergers with a sum of -36

Answer 1

Let the three consecutive integers be represented as \( x \), \( x + 1 \), and \( x + 2 \).

The sum of these integers can be written as:

\[
x + (x + 1) + (x + 2) = -36
\]

Simplifying the left side:

\[
3x + 3 = -36
\]

Next, subtract 3 from both sides:

\[
3x = -36 - 3
\]
\[
3x = -39
\]

Now, divide by 3:

\[
x = -13
\]

Thus, the three consecutive integers are:

\[
-13, -12, -11
\]

To verify, we can calculate their sum:

\[
-13 + (-12) + (-11) = -36
\]

The three consecutive integers are \(-13\), \(-12\), and \(-11\).