X/((.00025-X)(.001-x))

Hm. There's no way to solve for x at this point because this is an expression. Is this supposed to be set equal to anything? Like 0 or something?

X/((.00025-X)(.001-x))= 0

Ya it is equal to zero.

Oh. Then that makes it easier.

You see, since we're in the domain of real numbers (right?), the denominator of this fraction cannot equal 0. So X cannot be equal to .00025 or .001. X most certainly can equal any other real numbers, including 0.
Thus, X=all real numbers-{.00025,.001}. Hope this helped. Peace.

I don't agree with anonymous' answer

X/((.00025-X)(.001-x))= 0
multiply both sides by the denominator, then
x = 0

To solve for x in the equation X/((0.00025-X)(0.001-x)), you can follow these steps:

1. Start by multiplying out the denominator to get rid of the parentheses: (0.00025 - X)*(0.001 - x). Distribute the terms to get 0.00025*0.001 - X*0.001 - 0.00025*x + X*x.

2. Simplify the expression further by multiplying the terms: 0.00000025 - 0.001X - 0.00025x + X^2.

3. Now, combine like terms. Rewrite the equation in the standard form of a quadratic equation: X^2 - (0.001X + 0.00025x) + 0.00000025 = 0.

4. To solve the quadratic equation, you can use various methods such as factoring, completing the square, or using the quadratic formula. In this case, it's generally easier to use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the equation X^2 - (0.001X + 0.00025x) + 0.00000025 = 0, a = 1, b = -(0.001 + 0.00025), and c = 0.00000025.

Plugging in these values into the quadratic formula, you will get two possible solutions for x.

5. Simplify the values obtained from the quadratic formula to find the actual values of x.

Note: Quadratic equations can have two real solutions, one real solution (when the discriminant is zero), or two complex solutions (when the discriminant is negative).