Asked by Tiffany
Silver(I) nitrate and sodium sulfate react to form silver(I) sulfate and sodium nitrate.
Suppose 43.5 mL of 0.040 M silver(I) nitrate solution and 26.58 mL of 0.10 M sodium sulfate solution are mixed. What is the maximum number of grams of silver(I) sulfate that can be made?
Suppose 43.5 mL of 0.040 M silver(I) nitrate solution and 26.58 mL of 0.10 M sodium sulfate solution are mixed. What is the maximum number of grams of silver(I) sulfate that can be made?
Answers
Answered by
bobpursley
moles silver: .0435*.04
moles sulfate:.02658*.1
To make Ag2SO4, from the above, one is limiting. So of the two inputs above, which will be limiting?
moles sulfate:.02658*.1
To make Ag2SO4, from the above, one is limiting. So of the two inputs above, which will be limiting?
Answered by
Anonymous
silver
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