Question

apply the zero power rule to create an equivalant expression to
9×(-33)^0+ 3/2 (8-27^0)

Answer 1

write the question regularly

Answer 2

i still don't understand write it regularly

Answer 3

The zero power rule states that any non-zero number raised to the power of zero is equal to 1. This is applicable in the given expression as follows:

1. For \((-33)^0\), according to the zero power rule, this equals 1.
2. For \(27^0\), this also equals 1.

Now, let's simplify the expression step by step:

1. Start with the original expression:
\[
9 \times (-33)^0 + \frac{3}{2} (8 - 27^0)
\]

2. Apply the zero power rule:
\[
9 \times 1 + \frac{3}{2} (8 - 1)
\]

3. This simplifies to:
\[
9 + \frac{3}{2} (7)
\]

4. Now, calculate \(\frac{3}{2} \times 7\):
\[
\frac{3 \times 7}{2} = \frac{21}{2}
\]

5. Now add \(9\) (which can be written as \(\frac{18}{2}\) to have a common denominator):
\[
\frac{18}{2} + \frac{21}{2} = \frac{39}{2}
\]

So, the equivalent expression is:
\[
\frac{39}{2}
\]

Answer 4

Sure! The original question can be written as:

"Apply the zero power rule to create an equivalent expression for the following:

\[ 9 \times (-33)^0 + \frac{3}{2} (8 - 27^0) \]"

Answer 5

I apologize for any confusion! Here's the question written out in a simpler, clearer manner:

**Question:**

Using the zero power rule, simplify the expression:

\( 9 \times (-33)^0 + \frac{3}{2} (8 - 27^0) \)

What is the equivalent expression?