Question

apply the zero power rule to create an equivalant expression to
9×(-33)^0+ 3/2 (8-27^0)

Answer 1

To apply the zero power rule, we first note that any non-zero number raised to the power of zero is equal to 1. Therefore, we can simplify the expression step by step.

Starting with the expression:

\[
9 \times (-33)^0 + \frac{3}{2} (8 - 27^0)
\]

1. Simplify \( (-33)^0 \):
\[
(-33)^0 = 1
\]
Thus, \( 9 \times (-33)^0 = 9 \times 1 = 9 \).

2. Simplify \( 27^0 \):
\[
27^0 = 1
\]
Therefore, inside the parentheses:
\[
8 - 27^0 = 8 - 1 = 7
\]
So, \( \frac{3}{2} (8 - 27^0) = \frac{3}{2} \times 7 = \frac{21}{2} \).

Now substitute these simplified values back into the expression:

\[
9 + \frac{21}{2}
\]

To add these, we can express 9 as a fraction with a denominator of 2:

\[
9 = \frac{18}{2}
\]

Now we can add:

\[
\frac{18}{2} + \frac{21}{2} = \frac{18 + 21}{2} = \frac{39}{2}
\]

Thus, the equivalent expression is:

\[
\frac{39}{2}
\]