Asked by Standard C.
on a warm day(92 degrees F) an air filled balloon occupies a volume of .20m^3 and is under a pressure of 20.0 lbs/in^2. if the baloon is cooled to 32 degrees F in a refigerator while its pressure is reduced to 14.7 lb/in wat is the volume on the air in the container? (assume the air behaves as an ideal gas?
Answers
Answered by
drwls
Use the fact that PV/T remains constant.
V2/V1 = T2/T1 * P1/P2
The number of moles is assumed constant.
The temperatures must be absolute (Rankine or Kelvin.)
32F = 273 K = 491 R = T2
92F = 551 R = 306 K = T1
Pressures can remain in lb/in^2, since you are taking a ratio.
V2/V1 = (273/306)*(14.7/20.0)
V2/V1 = T2/T1 * P1/P2
The number of moles is assumed constant.
The temperatures must be absolute (Rankine or Kelvin.)
32F = 273 K = 491 R = T2
92F = 551 R = 306 K = T1
Pressures can remain in lb/in^2, since you are taking a ratio.
V2/V1 = (273/306)*(14.7/20.0)
Answered by
edward
.65496475
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