Asked by Paula

If you wish to warm 120 kg of water by 16°C for your bath, how much heat is required?
((The heat capacity of liquid water is 4186 J/(kg·oC) )

Q = M C *(delta T)

delta T = 16 C (it means "change in temperature)
M = 120 kg
C = 4186 J/(kg·oC

Multiply it out for the answer (Q, the heat required), in Joules

Answers

Answered by Anonymous
8037120
Answered by cor
660
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions