For a parabola such as yours, the axis of symmetry is very simple.
All you have to do is set x = 'the x value of the vertex'
so here
x = 6 is the axis of symmetry.
BTW, your parabola has a minimum rather than a maximum since it opens upwards.
That minimum is -37, and it occurs when x = 6
(the -b/(2a) is used to find the x of the vertex
The problem is f(x)=x^2-12x-1
I have all the rest of the problems done except where it says the equation of the line of symmetry is ????
I know the vertex is (6,-37), the maximum is 6 and I think that part of the equation is x= -b/2a
Is this correct?
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Thank you Reiny. The problem said what is the equation of the line of the symmetry so I guess I over thought things, lol. Trying to prepare for my final that is due in a couple days and my brain is on overload bad.
1 answer