Asked by Amy
d^2+8 8-d
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d^3-d d^3-d
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d^3-d d^3-d
Answers
Answered by
bobpursley
The denominators are the same, so combine the numerators
d2+8-8+d= d(d+1)
factor out a d from each term in the denominator, then you are left with a difference of squares, and then factor and one two terms will divide out.
d2+8-8+d= d(d+1)
factor out a d from each term in the denominator, then you are left with a difference of squares, and then factor and one two terms will divide out.
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