To determine if there is an outlier in the given set of temperatures, we can use the IQR (Interquartile Range) method.
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Sort the Data:
The temperatures in sorted order:- 71, 71, 74, 75, 75, 76, 77, 77, 87
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Find the First Quartile (Q1) and Third Quartile (Q3):
- Q1 (the median of the first half) is the average of the 2nd and 3rd numbers:
Q1 = (71 + 74) / 2 = 72.5 - Q3 (the median of the second half) is the average of the 7th and 8th numbers:
Q3 = (77 + 77) / 2 = 77
- Q1 (the median of the first half) is the average of the 2nd and 3rd numbers:
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Calculate the Interquartile Range (IQR):
- IQR = Q3 - Q1 = 77 - 72.5 = 4.5
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Determine the Outlier Boundaries:
- Lower Boundary = Q1 - 1.5 * IQR = 72.5 - 1.5 * 4.5 = 72.5 - 6.75 = 65.75
- Upper Boundary = Q3 + 1.5 * IQR = 77 + 1.5 * 4.5 = 77 + 6.75 = 83.75
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Identify Outliers:
- Any temperature below 65.75 or above 83.75 is considered an outlier.
From the list, 87°F is the only temperature that falls above the upper boundary of 83.75. Thus, 87°F is the outlier.