Question

Acetone , C3H6), is the main ingredient of nail polish remover. A solution is made up by adding 35.0 ml of acetone (d=0.790g/ml) to 50.0ml of ethyl alchole, C2H6O (d=0.789 g/ml). summing volumes are additive, calculate

(a). the mass percent of acetone in the solution.

(b). the volume percent of ethyl alchole in the solution.

(c). the mole fraction of acetone in the solution.

Note: Please work problem completely

Answer 1

Acetone , C3H6), is the main ingredient of nail polish remover. A solution is made up by adding 35.0 ml of acetone (d=0.790g/ml) to 50.0ml of ethyl alchole, C2H6O (d=0.789 g/ml). summing volumes are additive, calculate

(a). the mass percent of acetone in the solution.
<b> Using density, convert mL of each to grams, then sum them to get a total. Then %aceton = (mass acetone/total mass)*100 = ??</b>

(b). the volume percent of ethyl alcohol in the solution.
<b>Sum the volumes to get a total volume. Then %EtOH = (volume EtOH/total volume)*100 = ??</b>

(c). the mole fraction of acetone in the solution.
<b> Convert grams from part a into moles acetone and moles EtOH. Sum moles to get a total moles. Then
mole fraction acetone = (moles acetone/total moles) = ??
Post your work if you get stuck. </b>

Answer 2

a. 41.2%

b. 58.8%

c. 0.358 moles

Answer 3

a.) % mass of acetone= (mass of solute/mass of solute=mass of solvent)100
*to get the mass you must find the mass by getting it in the given density and volume.
=(2.65/27.65+39.45)100
=(27.65/67.1)100
=41.21%
b.) % volume of ethyl alcohol= (volume of ethyl alcohol/total volume)100
=(50/85)100
=58.82%