Asked by double checking
1. How many mL of acetone are needed to prepare a 10% v/v solution in 500 mL of methanol?
2. If a 500mL solution of n-propanol in water is prepared with 4mL of alcohol, what is the concentration of alcohol in % v/v?
I've never worked with %v/v before so I'm not sure if I worked the problems correctly but for the first one I got 50mL of acetone and for the second one I got that it would be 0.8%v/v.
2. If a 500mL solution of n-propanol in water is prepared with 4mL of alcohol, what is the concentration of alcohol in % v/v?
I've never worked with %v/v before so I'm not sure if I worked the problems correctly but for the first one I got 50mL of acetone and for the second one I got that it would be 0.8%v/v.
Answers
Answered by
bobpursley
correct, and correct.
Answered by
double checking
thank you!
Answered by
DrBob222
I think #1 needs more work.
%v/v = [(mL solute/mL SOLUTION)]*100 = ?
50 mL acetone + 500 mL methanol is more than 500 mL total volume.
Assuming the volumes are additive (probably they are not), then
[(50/550)]*100 = 9.1%
%v/v = [(mL solute/mL SOLUTION)]*100 = ?
50 mL acetone + 500 mL methanol is more than 500 mL total volume.
Assuming the volumes are additive (probably they are not), then
[(50/550)]*100 = 9.1%
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