Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Quadratic functions in standard form quick checkAsked by bob
Quadratic Functions in Standard Form Quick Check
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Sure! A quadratic function in standard form is typically written as:
\[ f(x) = ax^2 + bx + c \]
where:
- \( a \), \( b \), and \( c \) are constants,
- \( a \neq 0 \) (if \( a = 0 \), the function is linear, not quadratic).
Here are a few quick checks and properties related to quadratic functions in standard form:
### 1. Identifying \( a \), \( b \), and \( c \)
For the quadratic function \( f(x) = 2x^2 - 4x + 3 \):
- \( a = 2 \)
- \( b = -4 \)
- \( c = 3 \)
### 2. Determining the direction of the parabola
- If \( a > 0 \), the parabola opens **upwards**.
- If \( a < 0 \), the parabola opens **downwards**.
### 3. Finding the vertex
The x-coordinate of the vertex can be found using the formula:
\[ x = -\frac{b}{2a} \]
For the example \( f(x) = 2x^2 - 4x + 3 \):
- \( x = -\frac{-4}{2(2)} = \frac{4}{4} = 1 \)
### 4. Finding the axis of symmetry
The axis of symmetry is the line \( x = -\frac{b}{2a} \).
### 5. Finding the y-intercept
Substituting \( x = 0 \) into the equation gives us the y-intercept:
\[ f(0) = c \]
For \( f(x) = 2x^2 - 4x + 3 \):
- The y-intercept is \( f(0) = 3 \).
### 6. Solutions (Roots) of the Quadratic Equation
To find the solutions, we can use the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
### 7. Example Problem
Let's say we want to analyze the function:
\[ f(x) = -3x^2 + 6x - 2 \]
1. Identify \( a \), \( b \), and \( c \):
- \( a = -3 \)
- \( b = 6 \)
- \( c = -2 \)
2. Direction of the parabola: Since \( a < 0 \), it opens downwards.
3. Vertex:
- \( x = -\frac{6}{2(-3)} = 1 \)
- Find \( f(1) = -3(1)^2 + 6(1) - 2 = 1 \)
- Vertex is at \( (1, 1) \).
4. Axis of symmetry: \( x = 1 \).
5. Y-intercept: \( f(0) = -2 \).
6. Roots (if needed):
- Use quadratic formula:
- \( b^2 - 4ac = 6^2 - 4(-3)(-2) = 36 - 24 = 12 \) (positive, two distinct roots).
- Roots will be \( x = \frac{-6 \pm \sqrt{12}}{-6} = \frac{6 \pm 2\sqrt{3}}{6} = 1 \pm \frac{\sqrt{3}}{3} \).
Feel free to ask if you have specific questions or examples!
\[ f(x) = ax^2 + bx + c \]
where:
- \( a \), \( b \), and \( c \) are constants,
- \( a \neq 0 \) (if \( a = 0 \), the function is linear, not quadratic).
Here are a few quick checks and properties related to quadratic functions in standard form:
### 1. Identifying \( a \), \( b \), and \( c \)
For the quadratic function \( f(x) = 2x^2 - 4x + 3 \):
- \( a = 2 \)
- \( b = -4 \)
- \( c = 3 \)
### 2. Determining the direction of the parabola
- If \( a > 0 \), the parabola opens **upwards**.
- If \( a < 0 \), the parabola opens **downwards**.
### 3. Finding the vertex
The x-coordinate of the vertex can be found using the formula:
\[ x = -\frac{b}{2a} \]
For the example \( f(x) = 2x^2 - 4x + 3 \):
- \( x = -\frac{-4}{2(2)} = \frac{4}{4} = 1 \)
### 4. Finding the axis of symmetry
The axis of symmetry is the line \( x = -\frac{b}{2a} \).
### 5. Finding the y-intercept
Substituting \( x = 0 \) into the equation gives us the y-intercept:
\[ f(0) = c \]
For \( f(x) = 2x^2 - 4x + 3 \):
- The y-intercept is \( f(0) = 3 \).
### 6. Solutions (Roots) of the Quadratic Equation
To find the solutions, we can use the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
### 7. Example Problem
Let's say we want to analyze the function:
\[ f(x) = -3x^2 + 6x - 2 \]
1. Identify \( a \), \( b \), and \( c \):
- \( a = -3 \)
- \( b = 6 \)
- \( c = -2 \)
2. Direction of the parabola: Since \( a < 0 \), it opens downwards.
3. Vertex:
- \( x = -\frac{6}{2(-3)} = 1 \)
- Find \( f(1) = -3(1)^2 + 6(1) - 2 = 1 \)
- Vertex is at \( (1, 1) \).
4. Axis of symmetry: \( x = 1 \).
5. Y-intercept: \( f(0) = -2 \).
6. Roots (if needed):
- Use quadratic formula:
- \( b^2 - 4ac = 6^2 - 4(-3)(-2) = 36 - 24 = 12 \) (positive, two distinct roots).
- Roots will be \( x = \frac{-6 \pm \sqrt{12}}{-6} = \frac{6 \pm 2\sqrt{3}}{6} = 1 \pm \frac{\sqrt{3}}{3} \).
Feel free to ask if you have specific questions or examples!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.