Let's solve each equation step-by-step to match them with their solutions.
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Equation: \( 2i + 3 = 2i - 5 \)
Solution: Subtract \( 2i \) from both sides: \[ 3 = -5 \]
This is a contradiction. Therefore, it has no solution.
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Equation: \( 3i + 2i - 4 = 18i \)
Solution: Combine like terms on the left: \[ 5i - 4 = 18i \] Now, add \( 4 \) to both sides: \[ 5i = 18i + 4 \] Subtract \( 18i \) from both sides: \[ -13i = 4 \] Divide by \(-13\): \[ i = -\frac{4}{13} \]
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Equation: \( 3(2i - 7) = 6i - 21 \)
Solution: Distribute \( 3 \) on the left: \[ 6i - 21 = 6i - 21 \] This simplifies to an identity, which is true for all values of \( i \). Hence, the solution is all real numbers.
Summary of Matching:
- \( 2i + 3 = 2i - 5 \) → No solution
- \( 3i + 2i - 4 = 18i \) → \( i = -\frac{4}{13} \)
- \( 3(2i - 7) = 6i - 21 \) → All real numbers
So, we have:
- No solution: \( 2i + 3 = 2i - 5 \)
- \( i = -\frac{4}{13} \): \( 3i + 2i - 4 = 18i \)
- All real numbers: \( 3(2i - 7) = 6i - 21 \)