Match the equation with the line from the system shown on the graph. (2 points) Put responses in the correct input to answer the question. Select a response%2C navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar%2C enter key%2C left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Blue Line Purple Line
27 answers
In order to match the equations with the lines on the graph, it is necessary to have access to the graph or at least the equations. Without that information, it is not possible to provide the correct response.
Use your graphing calculator: Desmos Graphing Calculator Link Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost $4 and student tickets cost $2.50. The school makes $2,820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. (7 points) Put responses in the correct input to answer the question. Select a
I'm sorry, but I am not able to access specific websites or use external tools such as a graphing calculator. However, I can help you solve the problem algebraically.
Let's represent the number of adult tickets sold as "a" and the number of student tickets sold as "s".
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.5s.
The problem states that the school made $2,820 from ticket sales, so the equation representing this situation is:
4a + 2.5s = 2820
This equation can be used to find the cost of all adult and student tickets sold.
Let's represent the number of adult tickets sold as "a" and the number of student tickets sold as "s".
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.5s.
The problem states that the school made $2,820 from ticket sales, so the equation representing this situation is:
4a + 2.5s = 2820
This equation can be used to find the cost of all adult and student tickets sold.
Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold. (7 points) Put responses in the correct input to answer the question. Select a response%2C navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar%2C enter key%2C left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold.
The equation that represents this situation is:
4a + 2.50s = 2820
4a + 2.50s = 2820
Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820. Write an equation that represents this situation to find the cost of all adult and student tickets sold.900 tickets are sold for the spring fling. Write an equation to represent this situation. a %2B Response area %3D Response area
Let's use the variable "a" to represent the number of adult tickets sold and the variable "s" to represent the number of student tickets sold.
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.50s.
The equation representing the total cost of all tickets sold can be written as:
4a + 2.50s = 2820
In addition, we are told that a total of 900 tickets were sold for the Spring Fling. Therefore, we can also write an equation representing the total number of tickets sold as:
a + s = 900
So, the complete equation that represents this situation is:
a + s = 900
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.50s.
The equation representing the total cost of all tickets sold can be written as:
4a + 2.50s = 2820
In addition, we are told that a total of 900 tickets were sold for the Spring Fling. Therefore, we can also write an equation representing the total number of tickets sold as:
a + s = 900
So, the complete equation that represents this situation is:
a + s = 900
Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820.Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820.
The equation that represents this situation to find the cost of all adult and student tickets sold is:
4a + 2.50s = 2820
4a + 2.50s = 2820
Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820. Write an equation that represents this situation to find the cost of all adult and student tickets sold.Adult tickets cost %244 and student tickets cost %242.50. The school makes %242%2C820.
anonymous
answered
anonymous
answered
The equation that represents this situation to find the cost of all adult and student tickets sold is:
4a + 2.50s = 2820
where "a" represents the number of adult tickets sold and "s" represents the number of student tickets sold.
4a + 2.50s = 2820
where "a" represents the number of adult tickets sold and "s" represents the number of student tickets sold.
no
I apologize for the confusion. Let's start afresh.
Let's use the variable "a" to represent the number of adult tickets sold and the variable "s" to represent the number of student tickets sold.
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.50s.
The problem states that the school made $2,820 from ticket sales, so the equation representing this situation is:
4a + 2.50s = 2820
Furthermore, we are told that 900 tickets were sold for the Spring Fling. Therefore, we can write an equation representing the total number of tickets sold as:
a + s = 900
So, the complete set of equations that represents this situation is:
4a + 2.50s = 2820
a + s = 900
Let's use the variable "a" to represent the number of adult tickets sold and the variable "s" to represent the number of student tickets sold.
The cost of one adult ticket is $4, so the total cost of adult tickets sold would be 4a.
The cost of one student ticket is $2.50, so the total cost of student tickets sold would be 2.50s.
The problem states that the school made $2,820 from ticket sales, so the equation representing this situation is:
4a + 2.50s = 2820
Furthermore, we are told that 900 tickets were sold for the Spring Fling. Therefore, we can write an equation representing the total number of tickets sold as:
a + s = 900
So, the complete set of equations that represents this situation is:
4a + 2.50s = 2820
a + s = 900
what are the adult tickets and students tikets sold?
To find the number of adult tickets and student tickets sold, we can solve the system of equations:
4a + 2.50s = 2820
a + s = 900
Let's solve the second equation for "a" and substitute it into the first equation:
a = 900 - s
Substituting this expression for "a" into the first equation:
4(900 - s) + 2.50s = 2820
3600 - 4s + 2.50s = 2820
-1.50s = -780
s = 520
Now, we can substitute the value of "s" back into the equation a + s = 900:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, 380 adult tickets and 520 student tickets were sold.
4a + 2.50s = 2820
a + s = 900
Let's solve the second equation for "a" and substitute it into the first equation:
a = 900 - s
Substituting this expression for "a" into the first equation:
4(900 - s) + 2.50s = 2820
3600 - 4s + 2.50s = 2820
-1.50s = -780
s = 520
Now, we can substitute the value of "s" back into the equation a + s = 900:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, 380 adult tickets and 520 student tickets were sold.
Use the image to answer the question. Solving the system y%3D−x%2B3 and x%2By%3D8 by graphing shows that there is no solution to the system. Is this statement true or false%3F Explain. (1 point) Responses The statement is false%2C because the lines have an intersection point. The statement is false%2C because the lines have an intersection point. The statement is true%2C because the lines are parallel. The statement is true%2C because the lines are parallel. The statement is false%2C because the lines are parallel. The statement is false%2C because the lines are parallel. The statement is true%2C because the lines have an intersection point. The statement is true%2C because the lines have an intersection point.
The statement is false because the lines have an intersection point.
Use the image to answer the question. Does the graph show the system of equations x%2By%3D2 and −x%2By%3D7%3F Should the lines for the system be parallel%3F (1 point) Responses Both graphs are correct. The lines should be parallel. Both graphs are correct. The lines should be parallel. The graph of −x%2By%3D7 is incorrect. The lines should be parallel. The graph of negative x plus y equals 7 is incorrect. The lines should be parallel. The graph of −x%2By%3D7 is incorrect. The lines should intersect. The graph of negative x plus y equals 7 is incorrect. The lines should intersect. The graph of x%2By%3D2 is incorrect. The lines should intersect.
The graph of x + y = 2 and the graph of -x - y = 7 are correct for the given system of equations. The lines should be parallel.
One Solution%2C No Solution%2C or Many Solutions Quick Check 3 of 53 of 5 Items Question Which of these graphs shows that the linear system −2x%2By%3D6 and 4x−2y%3D−12 has an infinite number of solutions%3F(1 point) Responses Image with alt text%3A A coordinate plane with 4 quadrants shows x and y axes ranging from negative 10 to 10 in unit increments. Two parallel lines are plotted on the plane. A dotted upward slanting line with arrows at both ends passes through the points left parenthesis negative 3 comma 0 right parenthesis and left parenthesis 0 comma 6 right parenthesis. A solid upward slanting line with arrows at both ends%2C parallel to the dotted line%2C passes through origin. Image with alt text%3A A coordinate plane with 4 quadrants shows x and y axes ranging from negative 10 to 10 in unit increments. A line is plotted on the plane. An upward slanting line with arrows at both ends passes through the points left parenthesis negative 3 comma 0 right parenthesis and left parenthesis 0 comma 6 right parenthesis. Image with alt text%3A A coordinate plane with 4 quadrants shows x and y axes ranging from negative 10 to 10 in unit increments. Two intersecting lines are plotted on the plane. A solid upward slanting line with arrows at both ends passes through the points left parenthesis negative 3 comma 0 right parenthesis and left parenthesis 0 comma 6 right parenthesis. A dotted upward slanting line passes through the points left parenthesis 0 comma 6 right parenthesis and left parenthesis 1 comma 7 right parenthesis. Image with alt text%3A A coordinate plane with 4 quadrants shows x and y axes ranging from negative 10 to 10 in unit increments. A line is plotted on the plane. An upward slanting line with arrows at both ends passes through the points left parenthesis 0 comma negative 6 right parenthesis and left parenthesis 3 comma 0 right parenthesis. Skip to navigation
The graph that shows that the linear system -2x + y = 6 and 4x - 2y = -12 has an infinite number of solutions is the one with two intersecting lines.
Although there is no corresponding alt text provided, the key information is that the lines intersect. This indicates that there are multiple points of intersection between the lines and therefore an infinite number of solutions to the system of equations.
Although there is no corresponding alt text provided, the key information is that the lines intersect. This indicates that there are multiple points of intersection between the lines and therefore an infinite number of solutions to the system of equations.
One Solution%2C No Solution%2C or Many Solutions Quick Check 5 of 55 of 5 Items Question Solve the given system of linear equations by inspection. y%3D35x−5 y%3D−35x−5 (1 point) Responses (−5%2C0) left parenthesis negative 5 comma 0 right parenthesis infinitely many solutions infinitely many solutions no solution no solution (0%2C−5)
By inspection, we can see that the two equations are of the form y = mx - b where m is the slope and b is the y-intercept.
For the equation y = 35x - 5, the slope is 35 and the y-intercept is -5.
For the equation y = -35x - 5, the slope is -35 and the y-intercept is -5.
Since the slopes are opposite in sign and the y-intercepts are the same, the two lines are parallel. Parallel lines do not intersect and therefore, there is no solution to this system of equations.
So, the correct response is: no solution.
For the equation y = 35x - 5, the slope is 35 and the y-intercept is -5.
For the equation y = -35x - 5, the slope is -35 and the y-intercept is -5.
Since the slopes are opposite in sign and the y-intercepts are the same, the two lines are parallel. Parallel lines do not intersect and therefore, there is no solution to this system of equations.
So, the correct response is: no solution.
Question Use the image to answer the question. The graphs represent this system%3A y%3D3x−2 −3x%2By%3D7 How many solutions does this system have%3A 0%2C 1%2C or ∞ %3F (1 point)
Based on the information provided, we would need access to the image in order to determine the number of solutions for the system. Without being able to see the graph, it is not possible to determine the number of solutions (0, 1, or ∞).
If the lines in a system of linear equations are parallel%2C what is the system called%3F Enter the number that corresponds to the correct option%3A 1 - consistent system of equations 2 - dependent system of equations 3 - inconsistent system of equations 4 - independent system of equations (1 point)
If the lines in a system of linear equations are parallel, the system is called option 3 - an inconsistent system of equations.