Asked by Landon Sharp
What is the product of the polynomials (x2y+2)(x2−y)?(1 point)
Responses
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−x2y2+2x2−2y
Responses
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−x2y2+2x2−2y
Answers
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we will use the distributive property (also known as the FOIL method for binomials):
1. Distribute \(x^2y\) to both terms in the second polynomial:
\[
x^2y \cdot x^2 = x^4y
\]
\[
x^2y \cdot (-y) = -x^2y^2
\]
2. Now distribute \(2\) to both terms in the second polynomial:
\[
2 \cdot x^2 = 2x^2
\]
\[
2 \cdot (-y) = -2y
\]
Now combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
From the responses you provided, the correct answer is:
- \(x^4y - x^2y^2 + 2x^2 - 2y\)
1. Distribute \(x^2y\) to both terms in the second polynomial:
\[
x^2y \cdot x^2 = x^4y
\]
\[
x^2y \cdot (-y) = -x^2y^2
\]
2. Now distribute \(2\) to both terms in the second polynomial:
\[
2 \cdot x^2 = 2x^2
\]
\[
2 \cdot (-y) = -2y
\]
Now combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
From the responses you provided, the correct answer is:
- \(x^4y - x^2y^2 + 2x^2 - 2y\)