Question
What is the product of the polynomials (x2y+2)(x2−y) ?(1 point)
Responses
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−xy+x2y
Responses
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−xy+x2y
Answers
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y+2)(x^2−y)\), we can use the distributive property (also known as the FOIL method for binomials).
Let's expand the expression:
1. Multiply \(x^2y\) by \(x^2\):
\[
x^2y \cdot x^2 = x^4y
\]
2. Multiply \(x^2y\) by \(-y\):
\[
x^2y \cdot (-y) = -x^2y^2
\]
3. Multiply \(2\) by \(x^2\):
\[
2 \cdot x^2 = 2x^2
\]
4. Multiply \(2\) by \(-y\):
\[
2 \cdot (-y) = -2y
\]
Now, combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So, the product of the polynomials \((x^2y+2)(x^2−y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Among the provided options, the correct answer is:
**x^4y - x^2y^2 + 2x^2 - 2y**
Let's expand the expression:
1. Multiply \(x^2y\) by \(x^2\):
\[
x^2y \cdot x^2 = x^4y
\]
2. Multiply \(x^2y\) by \(-y\):
\[
x^2y \cdot (-y) = -x^2y^2
\]
3. Multiply \(2\) by \(x^2\):
\[
2 \cdot x^2 = 2x^2
\]
4. Multiply \(2\) by \(-y\):
\[
2 \cdot (-y) = -2y
\]
Now, combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So, the product of the polynomials \((x^2y+2)(x^2−y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Among the provided options, the correct answer is:
**x^4y - x^2y^2 + 2x^2 - 2y**