Question

The following table displays four solutions created through the dissolution of salt in water.
Solution: A. Mass of NaCl: 5.0 Volume of water: 50.0
Solution: B. Mass of NaCl: 5.0 Volume of water: 75.0
Solution: C. Mass of NaCl: 5.0 Volume of water: 100.0
Solution: D. Mass of NaCl: 5.0 Volume of water: 125.0
Among the provided solutions, which one exhibits the greatest concentration of salt?

Answer 1

To determine the concentration of salt (NaCl) in each solution, we can calculate the concentration using the formula:

\[
\text{Concentration (C)} = \frac{\text{mass of solute (g)}}{\text{volume of solvent (L)}}
\]

First, let's convert the volume of water from milliliters (mL) to liters (L) for each solution:

- Solution A:
- Volume = 50.0 mL = 0.050 L
- Concentration = \( \frac{5.0 \, \text{g}}{0.050 \, \text{L}} = 100 \, \text{g/L} \)

- Solution B:
- Volume = 75.0 mL = 0.075 L
- Concentration = \( \frac{5.0 \, \text{g}}{0.075 \, \text{L}} = \frac{5.0}{0.075} \approx 66.67 \, \text{g/L} \)

- Solution C:
- Volume = 100.0 mL = 0.100 L
- Concentration = \( \frac{5.0 \, \text{g}}{0.100 \, \text{L}} = 50 \, \text{g/L} \)

- Solution D:
- Volume = 125.0 mL = 0.125 L
- Concentration = \( \frac{5.0 \, \text{g}}{0.125 \, \text{L}} = 40 \, \text{g/L} \)

Now, summarizing the concentrations:

- Solution A: 100 g/L
- Solution B: 66.67 g/L
- Solution C: 50 g/L
- Solution D: 40 g/L

From these calculations, Solution A exhibits the greatest concentration of salt at 100 g/L.