Using the graph how would adding 5 and -2, then dividing by 2 help you find the midpoint of the line segment AB. A(2,-2) B(6,5)

It finds the y value that is average between the two y values of points.
It finds the sole midpoint of points A and B.
It finds the x value that is the average between the two x values of points.
It finds the distance between points A and B

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

To find the midpoint of a line segment defined by two points \(A(2,-2)\) and \(B(6,5)\), you use the midpoint formula, which calculates the average of the x-coordinates and the average of the y-coordinates.

1. **Finding the x-coordinate of the midpoint:**
- The x-coordinate of the midpoint is calculated as:
\[
\text{Midpoint}_x = \frac{x_A + x_B}{2} = \frac{2 + 6}{2} = \frac{8}{2} = 4
\]

2. **Finding the y-coordinate of the midpoint:**
- The y-coordinate is calculated similarly:
\[
\text{Midpoint}_y = \frac{y_A + y_B}{2} = \frac{-2 + 5}{2} = \frac{3}{2} = 1.5
\]

So, the midpoint \(M\) of the line segment \(AB\) is \(M(4, 1.5)\).

### Answer Selection
Now, looking at your options regarding what the calculation of adding 5 and -2, then dividing by 2, helps achieve:

- **It finds the y value that is average between the two y values of points.**
- This is correct when it refers to calculating the y-coordinate of the midpoint.

- **It finds the sole midpoint of points A and B.**
- This statement is a bit vague—it suggests finding the entire midpoint rather than distinguishing between x and y.

- **It finds the x value that is the average between the two x values of points.**
- This is correct when it refers to calculating the x-coordinate of the midpoint.

- **It finds the distance between points A and B.**
- This is incorrect; the average does not directly give distance.

Based on the specific question regarding \(5\) and \(-2\), that refers directly to the y-coordinates of points A and B, making the best answer **"It finds the y value that is average between the two y values of points."**