Question
Which of the AQUEOUS solutions is most probable to have resulted in the brightest glow of the bulb
NH3(aq) because it is a week electrolyte
C12H22O11(aq) because it is a non-electrolyte
KCI(aq) because it is a strong electrolyte
CH3OH(aq) Because it is an Electrolyte
NH3(aq) because it is a week electrolyte
C12H22O11(aq) because it is a non-electrolyte
KCI(aq) because it is a strong electrolyte
CH3OH(aq) Because it is an Electrolyte
Answers
Answered by
GPT-4o mini
To determine which aqueous solution is most likely to produce the brightest glow in a bulb, we need to consider the nature of each solution in terms of its ability to conduct electricity, which is directly related to its status as an electrolyte.
1. **NH3(aq)** - Ammonia is a weak electrolyte. It partially ionizes in water to produce NH4+ and OH- ions, but it does not dissociate completely. Therefore, it would conduct electricity poorly.
2. **C12H22O11(aq)** - Sucrose (table sugar) is a non-electrolyte. It does not dissociate into ions in solution, meaning it cannot conduct electricity at all.
3. **KCl(aq)** - Potassium chloride is a strong electrolyte. It completely dissociates into K+ and Cl- ions in solution, allowing for efficient conduction of electricity. This would likely result in a bright glow in the bulb.
4. **CH3OH(aq)** - Methanol is also a non-electrolyte. While it can dissolve in water and participate in some reactions, it does not produce ions and therefore does not conduct electricity significantly.
Based on this analysis, **KCl(aq)** is the most probable solution to produce the brightest glow in the bulb, as it is a strong electrolyte that fully dissociates in solution and allows for maximum electrical conductivity.
1. **NH3(aq)** - Ammonia is a weak electrolyte. It partially ionizes in water to produce NH4+ and OH- ions, but it does not dissociate completely. Therefore, it would conduct electricity poorly.
2. **C12H22O11(aq)** - Sucrose (table sugar) is a non-electrolyte. It does not dissociate into ions in solution, meaning it cannot conduct electricity at all.
3. **KCl(aq)** - Potassium chloride is a strong electrolyte. It completely dissociates into K+ and Cl- ions in solution, allowing for efficient conduction of electricity. This would likely result in a bright glow in the bulb.
4. **CH3OH(aq)** - Methanol is also a non-electrolyte. While it can dissolve in water and participate in some reactions, it does not produce ions and therefore does not conduct electricity significantly.
Based on this analysis, **KCl(aq)** is the most probable solution to produce the brightest glow in the bulb, as it is a strong electrolyte that fully dissociates in solution and allows for maximum electrical conductivity.