Question
Which of the aqueous solutions is most probable to have resulted in the brightest glow of the bulb?
(1 point)
Responses
KCl(aq) because it is a strong electrolyte
KCl( aq ) because it is a strong electrolyte
C12H22O11(aq) because it is a nonelectrolyte
C 12 H 22 O 11 ( aq ) because it is a nonelectrolyte
CH3OH(aq) because it is an electrolyte
CH 3 OH( aq ) because it is an electrolyte
NH3(aq) because it is a weak electrolyte
(1 point)
Responses
KCl(aq) because it is a strong electrolyte
KCl( aq ) because it is a strong electrolyte
C12H22O11(aq) because it is a nonelectrolyte
C 12 H 22 O 11 ( aq ) because it is a nonelectrolyte
CH3OH(aq) because it is an electrolyte
CH 3 OH( aq ) because it is an electrolyte
NH3(aq) because it is a weak electrolyte
Answers
GPT-4o mini
The brightness of a bulb in an electrical circuit with aqueous solutions is determined by the ability of the solution to conduct electricity, which is related to the presence of ions in solution.
- **KCl(aq)** is a strong electrolyte and completely dissociates into K\(^+\) and Cl\(^-\) ions in solution, making it a good conductor of electricity. This would result in a bright glow of the bulb.
- **C12H22O11(aq)** (sucrose) is a nonelectrolyte and does not dissociate into ions, so it would not conduct electricity and would not cause the bulb to glow.
- **CH3OH(aq)** (methanol) is also not a strong electrolyte; it does not ionize fully in solution, so it would not effectively conduct electricity as well as KCl.
- **NH3(aq)** (ammonia) is a weak electrolyte and only partially ionizes in solution. It can conduct electricity but not as well as a strong electrolyte like KCl.
Given these explanations, the solution that is most likely to produce the brightest glow of the bulb is:
**KCl(aq) because it is a strong electrolyte.**
- **KCl(aq)** is a strong electrolyte and completely dissociates into K\(^+\) and Cl\(^-\) ions in solution, making it a good conductor of electricity. This would result in a bright glow of the bulb.
- **C12H22O11(aq)** (sucrose) is a nonelectrolyte and does not dissociate into ions, so it would not conduct electricity and would not cause the bulb to glow.
- **CH3OH(aq)** (methanol) is also not a strong electrolyte; it does not ionize fully in solution, so it would not effectively conduct electricity as well as KCl.
- **NH3(aq)** (ammonia) is a weak electrolyte and only partially ionizes in solution. It can conduct electricity but not as well as a strong electrolyte like KCl.
Given these explanations, the solution that is most likely to produce the brightest glow of the bulb is:
**KCl(aq) because it is a strong electrolyte.**