A tall, heterozygous pea plant is crossed with another tall, heterozygous pea plant. What is the probability that an offspring will be a short plant?(1 point)

Question

Responses

75%
75%

50%
50%

25%
25%

0%

Answer 1

To determine the probability of a short pea plant offspring from a cross between two tall, heterozygous pea plants (Tt x Tt), we can use a Punnett square.

1. The alleles involved are:

   • T = tall (dominant)
   • t = short (recessive)

2. The possible gametes from each parent (Tt):

   • Parent 1: T and t
   • Parent 2: T and t

3. The Punnett square will look like this:

       T       t
     _______________
T |   TT    |  Tt   |
     _______________
t |   Tt    |  tt   |
     _______________

4. The genotypes of the potential offspring are:

   • TT (tall)
   • Tt (tall)
   • Tt (tall)
   • tt (short)

5. The resulting genotypic ratios are:

   • 1 TT : 2 Tt : 1 tt

This means:

• Tall plants (TT and Tt) = 3
• Short plants (tt) = 1

6. The probability of an offspring being a short plant (tt) is:
   • \( \frac{1}{4} \) or 25%

Therefore, the probability that an offspring will be a short plant is 25%.