A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point)

To determine the probability of obtaining a short, homozygous pea plant (tt) from a cross between two tall, heterozygous pea plants (Tt), we can use a Punnett square.

1. Set up the Punnett square with the gametes from each parent:

- One parent (Tt) can produce gametes: T and t
- The other parent (Tt) can also produce gametes: T and t

The Punnett square looks like this:

```
T t
______________
T | TT | Tt |
|__________|_______|
t | Tt | tt |
|__________|_______|
```

2. Now, let's analyze the possible genotypes of the offspring:

- **TT**: 1 square
- **Tt**: 2 squares
- **tt**: 1 square

3. From this, the genotypic ratio of the offspring is:
- TT: 1
- Tt: 2
- tt: 1

4. The probability of the offspring being short and homozygous (tt) is:
- There is 1 tt out of a total of 4 possible genotypes.

Thus, the probability is \( \frac{1}{4} = 25\% \).

So the correct response is:

**25%**