To find the quotient and remainder when dividing the polynomial \(12x^2 + 2x - 9\) by \(4x - 2\), we can use polynomial long division.
Steps to Divide:
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Divide the leading term of the dividend by the leading term of the divisor: \[ \frac{12x^2}{4x} = 3x \]
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Multiply the entire divisor by this result: \[ 3x(4x - 2) = 12x^2 - 6x \]
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Subtract this from the original polynomial: \[ (12x^2 + 2x - 9) - (12x^2 - 6x) = 2x + 6x - 9 = 8x - 9 \]
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Now repeat the process with the new polynomial \(8x - 9\): \[ \frac{8x}{4x} = 2 \]
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Multiply the divisor by this result: \[ 2(4x - 2) = 8x - 4 \]
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Subtract this from \(8x - 9\): \[ (8x - 9) - (8x - 4) = -9 + 4 = -5 \]
Final Results:
The quotient is \(3x + 2\) and the remainder is \(-5\).
Thus, we can express the polynomial as: \[ 12x^2 + 2x - 9 = (4x - 2)(3x + 2) - 5 \]
Confirming the Response:
The correct expression based on the calculations is: \[ 12x^2 + 2x - 9 = (4x - 2)(3x + 2) - 5 \]
Therefore, the correct answer is: 12x² + 2x - 9 = (4x - 2)(3x + 2) - 5.