Asked by Tiffany
how many grams of NaCN would you need to dossolve in enough water to make exactly 250.0mL of soultion with pH of 10.00?
Answers
Answered by
DrBob222
CN^- + HOH ==> HCN + OH^-
Kb = (Kw/Ka) = (HCN)(OH^-)/(CN^-)
You want pH to be 10 so pOH must be 4. Convert that to (OH^-) and plug into the Kb expression I have above. Solve for (CN^-) and the answer will be in molarity. Convert to grams NaCN/L of solution, then convert to 250 mL.
Kb = (Kw/Ka) = (HCN)(OH^-)/(CN^-)
You want pH to be 10 so pOH must be 4. Convert that to (OH^-) and plug into the Kb expression I have above. Solve for (CN^-) and the answer will be in molarity. Convert to grams NaCN/L of solution, then convert to 250 mL.
Answered by
yuppers
7.35 x 10^-3
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