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Redshift and Blueshift Quick Check
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Question
Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the two correct answers. (1 point)
Responses
Observer A and Observer B are both stationary and at the same distance from the object.
Observer A and Observer B are both stationary and at the same distance from the object.
Observer A and Observer B are moving at different speeds relative to each other.
Observer A and Observer B are moving at different speeds relative to each other.
Observer A is stationary and Observer B is moving.
Observer A is stationary and Observer B is moving.
Observer A and Observer B are stationary but at different distances from the vibrating object.
Observer A and Observer B are stationary but at different distances from the vibrating object.
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Answers
GPT-4o mini
The situations that might cause two observers (A and B) to measure different frequencies for the same vibrating object are:
1. **Observer A and Observer B are moving at different speeds relative to each other.**
This causes a Doppler effect, where the frequency observed by each observer changes based on their relative motion to the source of the sound.
2. **Observer A is stationary and Observer B is moving.**
In this scenario, the moving observer (B) would experience a Doppler shift, resulting in a different frequency measurement compared to the stationary observer (A).
The remaining options wouldn't cause a difference in measured frequencies since both observers are either stationary or at the same distance.
1. **Observer A and Observer B are moving at different speeds relative to each other.**
This causes a Doppler effect, where the frequency observed by each observer changes based on their relative motion to the source of the sound.
2. **Observer A is stationary and Observer B is moving.**
In this scenario, the moving observer (B) would experience a Doppler shift, resulting in a different frequency measurement compared to the stationary observer (A).
The remaining options wouldn't cause a difference in measured frequencies since both observers are either stationary or at the same distance.