Asked by Hannah
1) Find all the solutions of the equation in the interval (0,2pi).
sin 2x = -sqrt3/2
I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them.
2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi
Now I know that I have to divide by 2 but that is where I an not sure.
x = 4pi/6 + npi x=10pi/3 + npi
Is that correct???
sin 2x = -sqrt3/2
I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them.
2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi
Now I know that I have to divide by 2 but that is where I an not sure.
x = 4pi/6 + npi x=10pi/3 + npi
Is that correct???
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