The tv chef didn't know the first thing about cooking. He was just hired for his wavy blonde hair and charming british accent. So last tuesday while the gullible audience thought the chef was mixing up a world-renowned hollandaise sauce, he was actually just mixing a 5 ounce sauce containing 50% tangy mustard with another sauce containing 75% tangy mustard to get a sauce containing 70% tangy mustard. How many ounces of the 75% tangy mustard sauce must the chef have used?

5 answers

To solve this problem, we can use the concept of a weighted average. We want to find out how many ounces of the 75% tangy mustard sauce is needed to mix with the 5 ounces of a sauce that contains 50% tangy mustard to yield a final sauce that contains 70% tangy mustard.

Let:

  • \( x \) = ounces of 75% tangy mustard sauce used
  • The total volume of the mixture is 5 ounces, containing both sauces: \[ 5 = y + x \] where \( y \) is the amount of the 50% tangy mustard sauce. Since we're using 5 ounces in total, we can express \( y \) as: \[ y = 5 - x \]

Next, we need to consider the tangy mustard content from each sauce:

  • The 50% mustard sauce provides: \[ 0.50 \times (5 - x) \]

  • The 75% mustard sauce provides: \[ 0.75 \times x \]

The total tangy mustard content in the final mixture needs to equal the tangy mustard content from 70% of 5 ounces: \[ 0.70 \times 5 = 3.5 \]

Now we can set up the equation by summing the tangy mustard contributions: \[ 0.50(5 - x) + 0.75x = 3.5 \]

Now, we will simplify and solve for \( x \): \[ 2.5 - 0.50x + 0.75x = 3.5 \] \[ 2.5 + 0.25x = 3.5 \] Subtracting 2.5 from both sides: \[ 0.25x = 1 \] Dividing by 0.25: \[ x = \frac{1}{0.25} = 4 \]

Thus, the chef must have used 4 ounces of the 75% tangy mustard sauce. To find \( y \): \[ y = 5 - x = 5 - 4 = 1 \]

So the chef used 1 ounce of the 50% tangy mustard sauce.

To summarize, the chef used 4 ounces of the 75% tangy mustard sauce.

the answer is NOT four ounces. The amount of tangy mustard in the 50% sauce plus the amount of tangy mustard in the 75% sauce has to equal the amount of tangy mustard in the 70% sauce.

Let's solve the problem step-by-step to ensure we have the correct calculations.

We need to create a sauce with a total of 5 ounces that is 70% tangy mustard. This will consist of two sauces: one that is 50% tangy mustard and another that is 75% tangy mustard.

Let's denote:

  • \( x \): the amount of 75% tangy mustard sauce (in ounces).
  • \( y \): the amount of 50% tangy mustard sauce (in ounces).

We know that:

  1. The total volume of the mixture is 5 ounces: \[ x + y = 5 \]

  2. The amount of tangy mustard in each of the sauces should add up to the amount of tangy mustard in the mixture that is 70% tangy mustard.

Tangy Mustard Content

  • The amount of tangy mustard from the 50% sauce: \[ 0.50 \times y \]

  • The amount of tangy mustard from the 75% sauce: \[ 0.75 \times x \]

  • The total tangy mustard in the 70% sauce: \[ 0.70 \times 5 = 3.5 \]

Setting Up the Equation

Now we can set up the equation for the tangy mustard content: \[ 0.50y + 0.75x = 3.5 \]

Substituting for \( y \)

From the first equation \( x + y = 5 \), we can express \( y \) in terms of \( x \): \[ y = 5 - x \]

Substituting \( y \) in the tangy mustard equation: \[ 0.50(5 - x) + 0.75x = 3.5 \]

Expanding this gives us: \[ 2.5 - 0.50x + 0.75x = 3.5 \]

Combining like terms: \[ 2.5 + 0.25x = 3.5 \]

Solving for \( x \)

Now, subtract \( 2.5 \) from both sides: \[ 0.25x = 3.5 - 2.5 \] \[ 0.25x = 1 \]

Finally, divide by \( 0.25 \): \[ x = \frac{1}{0.25} = 4 \]

Finding \( y \)

Now, substituting back to find \( y \): \[ y = 5 - x = 5 - 4 = 1 \]

Conclusion

The chef must have used:

  • 4 ounces of the 75% tangy mustard sauce and
  • 1 ounce of the 50% tangy mustard sauce.

If this seems contradictory to you, please review the constraints provided or the details in the question again. The math confirms the amount of each sauce needed to achieve the desired tangy mustard percentage in the final mixture. Let me know if you'd like to clarify or explore further!

the correct answer is 20 ounces.

Let’s re-evaluate the problem step by step to reach the correct answer.

We want to create a total of 5 ounces of sauce that is 70% tangy mustard by mixing a sauce that is 50% tangy mustard with another sauce that is 75% tangy mustard.

Let's define:

  • \( x \) = ounces of the 75% tangy mustard sauce used.
  • \( y \) = ounces of the 50% tangy mustard sauce used.

From the problem, we know:

  1. \( x + y = 5 \) (total amount of sauce)
  2. The tangy mustard content must satisfy: \[ 0.50y + 0.75x = 0.70 \times 5 \]

Calculating the right side: \[ 0.70 \times 5 = 3.5 \text{ ounces of tangy mustard} \]

This leads to the equations:

  1. \( x + y = 5 \)
  2. \( 0.50y + 0.75x = 3.5 \)

Solving the equations

From the first equation, we can express \( y \) in terms of \( x \): \[ y = 5 - x \]

Substituting \( y \) into the second equation: \[ 0.50(5 - x) + 0.75x = 3.5 \]

Expanding this: \[ 2.5 - 0.50x + 0.75x = 3.5 \]

Combining like terms: \[ 2.5 + 0.25x = 3.5 \]

Subtracting 2.5 from both sides: \[ 0.25x = 1 \]

Dividing by 0.25: \[ x = 4 \]

Now, substitute back to find \( y \): \[ y = 5 - x = 5 - 4 = 1 \]

Final insights

So far, we derived that the amounts of the two sauces must be:

  • 1 ounce of the 50% tangy mustard sauce
  • 4 ounces of the 75% tangy mustard sauce

However, we are tasked with determining how many ounces of the 75% sauce are needed to achieve a specific outcome that would lead to the desired solution being stated as 20 ounces.

Re-evaluating the Conditions

If I misunderstood the context of your question regarding the total amounts being mixed, here’s how we can rethink the intended ratios scale:

  1. You may recall that the total volume of the desired sauce mix is 5 ounces, but are you considering how much raw ingredients (perhaps stock or a concentrated form) would be necessary for creating a larger batch?

If the chef needs a larger batch while maintaining the tangy mustard proportions and not limited to 5 ounces, we can adjust the amounts:

  • Suppose the final volume desired is greater than 5 ounces while maintaining the percentage needed.

Let’s say we want to find how many ounces of the 75% sauce could be used in a much larger quantity, such as aiming for a larger total volume (say expanding the 5 ounces into 20 for a broader recipe?).

To find how much of the 75% sauce is needed when the total target is now larger (for practical cooking) while maintaining the same combinatorial ratio in a 70% target:

Assuming \( V \) liters of a final mix, where \( V = 20 \):

  • Maintain: \[ 0.70 \times V = 14 \text{ ounces of tangy mustard} \]
  • Using proportions similar to our identified counts for tracking amounts of sauces used correctly.

The model must revisit blending ingredients that would pull in sufficiently larger scaling that resonates towards this broader scale, each coordinated correctly on concrete values.

If “20 ounces” was an instructive target rather than indicating actual amounts of the sauce combined, please specify if we target working from different yield amounts or focused kitchen ratios to correctly align on necessary measurements!

Let me know how you'd like to approach it specific to measuring or how to visualize the intended outcomes in recipes—thank you for your patience, and I appreciate your guidance as we solve this satisfactorily!