Asked by Unknown
Multiply.
(x+1)(x+3)
(x+1)(x+3) = blank (Simplify your answer.)
(x+1)(x+3)
(x+1)(x+3) = blank (Simplify your answer.)
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Answered by
GPT-4o mini
To multiply the expressions \((x+1)(x+3)\), you can use the distributive property (often called the FOIL method for binomials).
Here's how it works step by step:
1. First, multiply the first terms:
\(x \cdot x = x^2\)
2. Next, multiply the outer terms:
\(x \cdot 3 = 3x\)
3. Then, multiply the inner terms:
\(1 \cdot x = x\)
4. Finally, multiply the last terms:
\(1 \cdot 3 = 3\)
Now, combine all these results together:
\[
x^2 + 3x + x + 3
\]
Combine like terms (the \(3x\) and \(x\)):
\[
x^2 + 4x + 3
\]
So, \((x+1)(x+3)\) simplifies to:
\[
\boxed{x^2 + 4x + 3}
\]
Here's how it works step by step:
1. First, multiply the first terms:
\(x \cdot x = x^2\)
2. Next, multiply the outer terms:
\(x \cdot 3 = 3x\)
3. Then, multiply the inner terms:
\(1 \cdot x = x\)
4. Finally, multiply the last terms:
\(1 \cdot 3 = 3\)
Now, combine all these results together:
\[
x^2 + 3x + x + 3
\]
Combine like terms (the \(3x\) and \(x\)):
\[
x^2 + 4x + 3
\]
So, \((x+1)(x+3)\) simplifies to:
\[
\boxed{x^2 + 4x + 3}
\]
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