Question
Consider the following partially completed ANOVA and give the value of (g). / Beskou die onvoltooide ANOVA en gee die waarde van (g).
Source SS df MS Fstat Ftab
Treatments 142.67 (d) 35.6675 (g) (i)
Blocks 68.14 5 (f) (h) (j)
Errors (b) 20 1.9165
Total (c) (e)
Source SS df MS Fstat Ftab
Treatments 142.67 (d) 35.6675 (g) (i)
Blocks 68.14 5 (f) (h) (j)
Errors (b) 20 1.9165
Total (c) (e)
Answers
GPT-4o mini
To determine the value of \( g \) (the F-statistic for Treatments), we need to utilize the available information from the ANOVA table provided.
1. We know that \( F \) is calculated as follows:
\[
F = \frac{MS_{Treatments}}{MS_{Errors}}
\]
where \( MS \) represents the Mean Square.
2. The given data includes:
- \( MS_{Treatments} = 35.6675 \)
- \( MS_{Errors} = 1.9165 \)
3. We can plug these values into the formula for \( F \):
\[
F_{Treatments} = \frac{35.6675}{1.9165}
\]
4. Now let's calculate \( F \):
\[
F_{Treatments} \approx \frac{35.6675}{1.9165} \approx 18.60
\]
Thus, the value of \( g \) is approximately **18.60**.
If you need further details or calculations for other parts of the ANOVA, let me know!
1. We know that \( F \) is calculated as follows:
\[
F = \frac{MS_{Treatments}}{MS_{Errors}}
\]
where \( MS \) represents the Mean Square.
2. The given data includes:
- \( MS_{Treatments} = 35.6675 \)
- \( MS_{Errors} = 1.9165 \)
3. We can plug these values into the formula for \( F \):
\[
F_{Treatments} = \frac{35.6675}{1.9165}
\]
4. Now let's calculate \( F \):
\[
F_{Treatments} \approx \frac{35.6675}{1.9165} \approx 18.60
\]
Thus, the value of \( g \) is approximately **18.60**.
If you need further details or calculations for other parts of the ANOVA, let me know!
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