Consider the following partially completed ANOVA, and answer the following: give the value of (C). / Beskou die onvoltooide ANOVA en beantwoord die volgende: gee die waarde van (C).

To find the missing values in the ANOVA table, we can use the following relationships:

1. Degrees of Freedom (df):
- For Treatment: df = k - 1, where k is the number of treatments.
- For Error: df = N - k, where N is the total number of observations and k is the number of treatments.
- Total df = N - 1.

2. Sum of Squares (SS):
- Total SS = Treatment SS + Error SS.
- SS values can be calculated as:
- MS (Mean Square) = SS / df.
- Therefore, SS = MS * df.

3. F-statistic:
- F-statistic = MS(Treatment) / MS(Error).

From the provided ANOVA table, we can see that:

- For Treatment:
- SS = A
- df = 2
- MS = 43,024.778
- Fstat = 25.1754

- For Error:
- SS = 10,254
- df = C
- MS = E

- Total:
- SS = B
- df = D

### Steps to find missing values:

1. **Calculate Treatment SS (A):**
\[ A = MS_{Treatment} \times df_{Treatment} \]
\[ A = 43,024.778 \times 2 \]
\[ A = 86,049.556 \]

2. **Compute Total SS (B):**
\[ B = A + Error \, SS = A + 10,254 \]
\[ B = 86,049.556 + 10,254 = 96,303.556 \]

3. **Calculate Error df (C):**
Since we don’t have N, let’s express C in terms of N and k.
We know:
\[ Total \, df = (N - 1) \]
Since Total df = Treatment df + Error df:
\[ C = N - k \]
Given that Treatment df = 2, hence \( k = 3 \).
Therefore:
\[ Total \, df = (N - 1) = (N - 3 + 2); \]
So N = C + 1.

The missing information remains about N; let’s estimate the Error df (C) directly depending on how many total treatments we might have.

4. **Using F-statistic: Calculate Error MS (E):**
\[ E = \frac{SS_{Error}}{df_{Error}} \]
\[ \text{Given that } msTreatment = 43024.778, \text{ and Fstat = 25.1754} \]
\[ \frac{43,024.778}{E} = 25.1754 \rightarrow E = \frac{43,024.778}{25.1754} \approx 1,706.166 \]

Thus, using \( C \):
\[ 10,254 = E \times C, \{1,706.166 \times C = 10,254 \}. \]

5. **Solving for C:**
\[ C = \frac{10,254}{1,706.166} \approx 6 \]

So \( C \) = 6.

### Final Values:
- Treatment SS (A) = 86,049.556
- Error df (C) = 6
- Total SS (B) = 96,303.556

Now you have the value of C, which is **6**.