Question
Which example correctly demonstrates polynomial subtraction?(1 point) Responses
A. (2x^2+6x+1)−(3x^2+3x+9)=5x2+9x+10
B. (2x^2+6x+1)−(3x^2+3x+9)=−x2+3x−8
C. (2x^2+6x+1)−(3x^2+3x+9)=−5x2+3x−8
D. (2x^2+6x+1)−(3x^2+3x+9)=x2+3x+8
A. (2x^2+6x+1)−(3x^2+3x+9)=5x2+9x+10
B. (2x^2+6x+1)−(3x^2+3x+9)=−x2+3x−8
C. (2x^2+6x+1)−(3x^2+3x+9)=−5x2+3x−8
D. (2x^2+6x+1)−(3x^2+3x+9)=x2+3x+8
Answers
Answered by
GPT-4o mini
To demonstrate polynomial subtraction, you need to subtract each corresponding term of the polynomial being subtracted from the polynomial that is being subtracted from.
Let's calculate the subtraction of the polynomials in the options:
Given:
\[(2x^2 + 6x + 1) - (3x^2 + 3x + 9)\]
We can distribute the negative sign through the second polynomial:
\[
= 2x^2 + 6x + 1 - 3x^2 - 3x - 9
\]
Now, combine the like terms:
- For \(x^2\) terms: \(2x^2 - 3x^2 = -x^2\)
- For \(x\) terms: \(6x - 3x = 3x\)
- For constant terms: \(1 - 9 = -8\)
Putting it all together:
\[
= -x^2 + 3x - 8
\]
Comparing this result to the options given:
- A. Incorrect
- B. Correct: \((2x^2 + 6x + 1) - (3x^2 + 3x + 9) = -x^2 + 3x - 8\)
- C. Incorrect
- D. Incorrect
Thus, the correct answer is B. \((2x^2 + 6x + 1) - (3x^2 + 3x + 9) = -x^2 + 3x - 8\).
Let's calculate the subtraction of the polynomials in the options:
Given:
\[(2x^2 + 6x + 1) - (3x^2 + 3x + 9)\]
We can distribute the negative sign through the second polynomial:
\[
= 2x^2 + 6x + 1 - 3x^2 - 3x - 9
\]
Now, combine the like terms:
- For \(x^2\) terms: \(2x^2 - 3x^2 = -x^2\)
- For \(x\) terms: \(6x - 3x = 3x\)
- For constant terms: \(1 - 9 = -8\)
Putting it all together:
\[
= -x^2 + 3x - 8
\]
Comparing this result to the options given:
- A. Incorrect
- B. Correct: \((2x^2 + 6x + 1) - (3x^2 + 3x + 9) = -x^2 + 3x - 8\)
- C. Incorrect
- D. Incorrect
Thus, the correct answer is B. \((2x^2 + 6x + 1) - (3x^2 + 3x + 9) = -x^2 + 3x - 8\).
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