Asked by iintense
Hi, I'm just confused as to what steps to take in order to solve these problems.
If you could please show your steps and method on how to approach these questions to get the answer that would be great. I have the answers to these too, if needed. I want to know how to solve them though.
1) An elevator (mass 4850kg) is to be designed so that the maximum acceleration is 0.0680g. What are the maximum and minimum forces the motor should exert on the supporting cable?
2) A person stands on a bathroom scale in a still (motionless) elevator. When the elevator begins to move, the scale briefly reads only 0.75 of the person's regular weight. Calculate the acceleration of the elevator and find the direction of acceleration.
3) a)What is the acceleration of two falling sky divers (mass 132kg) when the upward force of air resistance is equal to one-fourth of their weight?
b) After popping open the parachute, the divers descend leisurely to the ground at constant speed. What now is the force of air resistance on the sky divers and their parachute?
Thank you for your time!
If you could please show your steps and method on how to approach these questions to get the answer that would be great. I have the answers to these too, if needed. I want to know how to solve them though.
1) An elevator (mass 4850kg) is to be designed so that the maximum acceleration is 0.0680g. What are the maximum and minimum forces the motor should exert on the supporting cable?
2) A person stands on a bathroom scale in a still (motionless) elevator. When the elevator begins to move, the scale briefly reads only 0.75 of the person's regular weight. Calculate the acceleration of the elevator and find the direction of acceleration.
3) a)What is the acceleration of two falling sky divers (mass 132kg) when the upward force of air resistance is equal to one-fourth of their weight?
b) After popping open the parachute, the divers descend leisurely to the ground at constant speed. What now is the force of air resistance on the sky divers and their parachute?
Thank you for your time!
Answers
Answered by
Damon
Net force on mass = mass * acceleration
1)
accelerating up
T - 4850*9.8 = 4850 *.068
accelerating down
T - 4850*9.8 = -4850*.068
2) define up as +
- m g + .75 m g = m a
so
a = -.25 g
accelerating down
3)a) 132 *9.8 - .25*132*9.8 = 132 a
b) 132*9.8 -air resistance = 132*0
1)
accelerating up
T - 4850*9.8 = 4850 *.068
accelerating down
T - 4850*9.8 = -4850*.068
2) define up as +
- m g + .75 m g = m a
so
a = -.25 g
accelerating down
3)a) 132 *9.8 - .25*132*9.8 = 132 a
b) 132*9.8 -air resistance = 132*0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.