Asked by Stephanie
I am having such a hard time in this class. Hopefully someone here can help me to understand some of what they are trying to teach me. I have a problem here and have been working on it for about an hour now and I can not figure it out. I need to come up with an answer but I need to understand it too so if someone helps me could you please break things down for me so that I learn. Thank you.
I have to subtract and then simplify if possible.
the problem is....
(4-v)over(v-6) minus (2v-5)over(6-v).
I hope I put that on there to where someone can understand it because I have a hard time trying to figure out how to even get them on a computer for some of my assignments.
I have to subtract and then simplify if possible.
the problem is....
(4-v)over(v-6) minus (2v-5)over(6-v).
I hope I put that on there to where someone can understand it because I have a hard time trying to figure out how to even get them on a computer for some of my assignments.
Answers
Answered by
drwls
(4-v)/(v-6) - (2v-5)/(6-v)
You can change the sign of the denominator of the second term and change the - to + at the same time.
That gives you
= (4-v)/(v-6) + (2v-5)/(v-6)
Now that you have a common denominator, you can add the numerators together.
= (4 - v + 2v -5)/(v-6)
= (v-1)/(v-6)
You can change the sign of the denominator of the second term and change the - to + at the same time.
That gives you
= (4-v)/(v-6) + (2v-5)/(v-6)
Now that you have a common denominator, you can add the numerators together.
= (4 - v + 2v -5)/(v-6)
= (v-1)/(v-6)
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