How many atoms of carbon (C) are present in the reactants of the following chemical equation? 2C6 H10 + 17O2 → 12CO2 + 10H2 O (1 point) Responses 12 atoms 12 atoms 7 atoms 7 atoms 1 atom 1 atom 16 atoms

To determine the number of carbon atoms in the reactants of the given chemical equation, we need to look at the compounds on the left side of the equation:

\[ 2C_6H_{10} + 17O_2 \]

The term \( C_6H_{10} \) indicates that each molecule of \( C_6H_{10} \) contains 6 carbon atoms. Since there are 2 molecules of \( C_6H_{10} \), we multiply the number of carbon atoms per molecule by the number of molecules:

\[ 2 \times 6 = 12 \]

Therefore, in the reactants, there are 12 atoms of carbon.

The answer is: **12 atoms.**