Asked by Snow Princess
simplify: x^675/x^453
Answers
Answered by
Snow Princess
what is the missing exponent in the following equation?
e^?/e^65=e^38
e^?/e^65=e^38
Answered by
Snow Princess
x^38/x^65=e^?
Answered by
GPT-4o mini
To simplify the expression \( \frac{x^{675}}{x^{453}} \), you can use the property of exponents that states \( \frac{a^m}{a^n} = a^{m-n} \).
Applying this property:
\[
\frac{x^{675}}{x^{453}} = x^{675 - 453}
\]
Now, subtract the exponents:
\[
675 - 453 = 222
\]
So, the simplified expression is:
\[
x^{222}
\]
Applying this property:
\[
\frac{x^{675}}{x^{453}} = x^{675 - 453}
\]
Now, subtract the exponents:
\[
675 - 453 = 222
\]
So, the simplified expression is:
\[
x^{222}
\]
Answered by
GPT-4o mini
To find the missing exponent in the equation
\[
\frac{e^{?}}{e^{65}} = e^{38},
\]
you can use the property of exponents that states
\[
\frac{e^a}{e^b} = e^{a - b}.
\]
Applying this to the left side of the equation:
\[
\frac{e^{?}}{e^{65}} = e^{? - 65}.
\]
Setting this equal to the right side of the equation gives:
\[
e^{? - 65} = e^{38}.
\]
Since the bases are the same, you can set the exponents equal to each other:
\[
? - 65 = 38.
\]
Now, solve for the missing exponent:
\[
? = 38 + 65 = 103.
\]
Thus, the missing exponent is
\[
\boxed{103}.
\]
\[
\frac{e^{?}}{e^{65}} = e^{38},
\]
you can use the property of exponents that states
\[
\frac{e^a}{e^b} = e^{a - b}.
\]
Applying this to the left side of the equation:
\[
\frac{e^{?}}{e^{65}} = e^{? - 65}.
\]
Setting this equal to the right side of the equation gives:
\[
e^{? - 65} = e^{38}.
\]
Since the bases are the same, you can set the exponents equal to each other:
\[
? - 65 = 38.
\]
Now, solve for the missing exponent:
\[
? = 38 + 65 = 103.
\]
Thus, the missing exponent is
\[
\boxed{103}.
\]
Answered by
GPT-4o mini
To simplify the expression \( \frac{x^{38}}{x^{65}} \), you can use the property of exponents that states
\[
\frac{a^m}{a^n} = a^{m-n}.
\]
Applying this property:
\[
\frac{x^{38}}{x^{65}} = x^{38 - 65} = x^{-27}.
\]
Now, the equation can be rewritten as:
\[
x^{-27} = e^{?}.
\]
At this point, to express \( x^{-27} \) in terms of \( e \), you can use the natural logarithm and the fact that \( x = e^{\ln(x)} \):
\[
x^{-27} = e^{-27 \ln(x)}.
\]
Therefore, we can set:
\[
e^{?} = e^{-27 \ln(x)}.
\]
This gives us:
\[
? = -27 \ln(x).
\]
So, the answer is
\[
\boxed{-27 \ln(x)}.
\]
\[
\frac{a^m}{a^n} = a^{m-n}.
\]
Applying this property:
\[
\frac{x^{38}}{x^{65}} = x^{38 - 65} = x^{-27}.
\]
Now, the equation can be rewritten as:
\[
x^{-27} = e^{?}.
\]
At this point, to express \( x^{-27} \) in terms of \( e \), you can use the natural logarithm and the fact that \( x = e^{\ln(x)} \):
\[
x^{-27} = e^{-27 \ln(x)}.
\]
Therefore, we can set:
\[
e^{?} = e^{-27 \ln(x)}.
\]
This gives us:
\[
? = -27 \ln(x).
\]
So, the answer is
\[
\boxed{-27 \ln(x)}.
\]
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