Which of the following options contains two coefficients and three terms?

#1: 2x - 3 = 4 - y
#2: 6 + 7y = 5
#3: 9x = 1 - 8x

1 answer

To determine which of the given equations contains two coefficients and three terms, we first need to analyze each option:

  1. #1: \( 2x - 3 = 4 - y \)

    • Rearranging this equation gives us: \( 2x - y - 3 - 4 = 0 \) or \( 2x - y - 7 = 0 \).
    • This has three terms: \( 2x \), \(-y\), and \(-7\).
    • Coefficients are \( 2 \) (of \( x \)) and \( -1 \) (of \( y \)).
    • This option contains two coefficients and three terms.
  2. #2: \( 6 + 7y = 5 \)

    • Rearranging gives us \( 7y + 6 - 5 = 0\) or \( 7y + 1 = 0 \).
    • This has two terms: \( 7y \) and \( 1 \).
    • There is only one coefficient, which is \( 7 \) (of \( y \)).
    • This option does not satisfy the requirements.
  3. #3: \( 9x = 1 - 8x \)

    • Rearranging gives us \( 9x + 8x - 1 = 0 \) or \( 17x - 1 = 0 \).
    • This has two terms: \( 17x \) and \(-1\).
    • There is only one coefficient, which is \( 17 \) (of \( x \)).
    • This option does not satisfy the requirements.

Based on the analysis:

  • Only option #1 contains two coefficients and three terms.