Question

Which of the following options contains two coefficients and three terms?

Option #1: 2x−3=4−y

Option #2: 6+7y=5

Option #3: 9x=1−8x

(1 point)
Option #
contains two coefficients and three terms.
Remaining Attempts : 2View previous attempt
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Answer 1

To determine which option contains two coefficients and three terms, let's analyze each option:

**Option #1: \(2x - 3 = 4 - y\)**
Rearranging it gives: \(2x - y - 7 = 0\)
Terms: \(2x\), \(-y\), \(-7\)
Coefficients: \(2\) (for \(x\)), \(-1\) (for \(y\))
Total terms: 3
Total coefficients: 2

**Option #2: \(6 + 7y = 5\)**
Rearranging gives: \(7y + 1 = 0\)
Terms: \(7y\), \(1\)
Coefficients: \(7\) (for \(y\))
Total terms: 2
Total coefficients: 1

**Option #3: \(9x = 1 - 8x\)**
Rearranging it gives: \(9x + 8x - 1 = 0\)
Terms: \(9x\), \(8x\), \(-1\)
Coefficients: \(9\) (for \(x\)), \(8\) (for \(x\) again)
Total terms: 3
Total coefficients: 1

Considering all options, **Option #1** meets the criteria of having **two coefficients and three terms**.

Thus, the answer is: **Option #1**.