Question

Solve the inequality Ay+3<12 where a is a number greater than 0

Answer 1

To solve the inequality \( Ay + 3 < 12 \) where \( a \) is a positive number, we can follow these steps:

1. **Isolate the term with \( y \)**:
\[
Ay + 3 < 12
\]
Subtract 3 from both sides:
\[
Ay < 12 - 3
\]
\[
Ay < 9
\]

2. **Divide by \( A \)**:
Since \( a \) is greater than 0, we can safely divide both sides by \( a \) without changing the direction of the inequality:
\[
y < \frac{9}{a}
\]

Thus, the solution to the inequality \( Ay + 3 < 12 \) is:
\[
y < \frac{9}{a}
\]
where \( a > 0 \).