Solve the inequality Ay+3<12 where a is a number greater than 0

Answer 1

To solve the inequality \( Ay + 3 < 12 \) where \( a \) is a positive number, we can follow these steps:

1. Isolate the term with \( y \): \[ Ay + 3 < 12 \] Subtract 3 from both sides: \[ Ay < 12 - 3 \] \[ Ay < 9 \]

2. Divide by \( A \): Since \( a \) is greater than 0, we can safely divide both sides by \( a \) without changing the direction of the inequality: \[ y < \frac{9}{a} \]

Thus, the solution to the inequality \( Ay + 3 < 12 \) is: \[ y < \frac{9}{a} \] where \( a > 0 \).