3.

Solve the inequality.



–7 > x > 6

–6 < x < 6

–32 < x < 20

1 answer

To solve the inequalities provided, let’s analyze each one:

  1. –7 > x > 6: This can be rewritten as two separate inequalities:

    • \( x < -7 \)
    • \( x > 6 \) This means that \( x \) is either less than -7 or greater than 6, which provides two distinct intervals:
    • \( (-\infty, -7) \) and \( (6, \infty) \)
  2. –6 < x < 6: This inequality means:

    • \( x \) is greater than -6 and less than 6 This provides a single interval:
    • \( (-6, 6) \)
  3. –32 < x < 20: Similar to the previous one, this means:

    • \( x \) is greater than -32 and less than 20 This provides another single interval:
    • \( (-32, 20) \)

To summarize:

  • The solution to \( -7 > x > 6 \) is: \( (-\infty, -7) \cup (6, \infty) \)
  • The solution to \( -6 < x < 6 \) is: \( (-6, 6) \)
  • The solution to \( -32 < x < 20 \) is: \( (-32, 20) \)

If you need further steps, like finding intersections or unions between these intervals, please specify!