Asked by Anonymous
In one of the original Doppler experiments, one tuba was played on a moving platform car at a frequency of 75 Hz, and a second identical one was played on the same tone while at rest in the railway station. What beat frequency was heard if the train approached the station at a speed of 18.0 m/s?
Answers
Answered by
bobpursley
calculate the doppler frequency , then the difference in that and 75 is the beat.
Answered by
Fe
that answer is not helpful enough to someone who is struggling with the material.
f'=f(v)/(v-vs)=75(340)/(340-18)=DO MATH
fbeat=f'-f
so sub f from calculated #
f'=f(v)/(v-vs)=75(340)/(340-18)=DO MATH
fbeat=f'-f
so sub f from calculated #
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