Asked by N.
                A Doppler blood flow meter emits ultrasound at a frequency of 5.0 MHz. What is the beat frequency between the emitted waves and the waves reflected from blood cells moving away from the emitter at 0.15m/s? Assume that v_sound=1540m/s in blood.
            
            
        Answers
                    Answered by
            drwls
            
    The Doppler shift, delta f, of the blood cells moving away is 2 V/v_sound * 5.0 *10^6 Hz. 
V = 0.15 m/s = the blood cell speed and v_sound = 1540 m/s.
The factor of 2 is there because the frequency is shifted twice (when received and when sent back).
delta f = 2*5*10^6*0.15/1540 = 974 Hz
The beat frequency (of the transmitted beam combined with the reflected beam)equals delta f
    
V = 0.15 m/s = the blood cell speed and v_sound = 1540 m/s.
The factor of 2 is there because the frequency is shifted twice (when received and when sent back).
delta f = 2*5*10^6*0.15/1540 = 974 Hz
The beat frequency (of the transmitted beam combined with the reflected beam)equals delta f
                    Answered by
            N.
            
    thank you Drwls
    
                    Answered by
            lizz
            
    thank you 
    
                    Answered by
            Michael
            
    perfect answer...thank you so much
    
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