Question
A ball is rolling down a hill with an initial velocity of 3 m/s. After 10 seconds, it is rolling 8 m/s. What is
the acceleration of the ball?
answers:
5 m/s^2
50 m/s^2
0.5 m/s^2
2 m/s^2
the acceleration of the ball?
answers:
5 m/s^2
50 m/s^2
0.5 m/s^2
2 m/s^2
Answers
GPT-4o mini
To find the acceleration of the ball, we can use the formula for acceleration, which is given by:
\[
a = \frac{v_f - v_i}{t}
\]
where:
- \(v_f\) is the final velocity,
- \(v_i\) is the initial velocity,
- \(t\) is the time.
Here, the initial velocity \(v_i = 3 \, \text{m/s}\), the final velocity \(v_f = 8 \, \text{m/s}\), and the time \(t = 10 \, \text{s}\).
Plugging the values into the formula:
\[
a = \frac{8 \, \text{m/s} - 3 \, \text{m/s}}{10 \, \text{s}} = \frac{5 \, \text{m/s}}{10 \, \text{s}} = 0.5 \, \text{m/s}^2
\]
So the acceleration of the ball is \(0.5 \, \text{m/s}^2\).
The correct answer is \(0.5 \, \text{m/s}^2\).
\[
a = \frac{v_f - v_i}{t}
\]
where:
- \(v_f\) is the final velocity,
- \(v_i\) is the initial velocity,
- \(t\) is the time.
Here, the initial velocity \(v_i = 3 \, \text{m/s}\), the final velocity \(v_f = 8 \, \text{m/s}\), and the time \(t = 10 \, \text{s}\).
Plugging the values into the formula:
\[
a = \frac{8 \, \text{m/s} - 3 \, \text{m/s}}{10 \, \text{s}} = \frac{5 \, \text{m/s}}{10 \, \text{s}} = 0.5 \, \text{m/s}^2
\]
So the acceleration of the ball is \(0.5 \, \text{m/s}^2\).
The correct answer is \(0.5 \, \text{m/s}^2\).