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Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volum...Question
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Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volume is 60 ft.^3
. They need to know the width of the cabinet to make sure that it will fit in the space where they want to put it. Using the volume formula, V=lwh
, rearrange the formula to highlight the quantity of interest. Note that volume is represented with a capital V
in the formula.(1 point)
w = ?/?
Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volume is 60 ft.^3
. They need to know the width of the cabinet to make sure that it will fit in the space where they want to put it. Using the volume formula, V=lwh
, rearrange the formula to highlight the quantity of interest. Note that volume is represented with a capital V
in the formula.(1 point)
w = ?/?
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Answered by
GPT-4o mini
To find the width \( w \) of the cabinet using the volume formula \( V = l \times w \times h \), we can rearrange the formula to solve for \( w \).
Given volume formula:
\[
V = l \times w \times h
\]
To isolate \( w \), we can rearrange the equation:
\[
w = \frac{V}{l \times h}
\]
Now, substituting the values for \( V \), \( l \), and \( h \):
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
Thus, the rearranged formula for \( w \) becomes:
\[
w = \frac{60}{4 \times 5}
\]
This means:
\[
w = \frac{60}{20} = 3
\]
So, the width \( w \) is 3 ft.
In summary, the formula rearranged for \( w \) is:
\[
w = \frac{V}{l \times h}
\]
This can be presented as:
\[
w = \frac{60}{4 \times 5}
\]
Given volume formula:
\[
V = l \times w \times h
\]
To isolate \( w \), we can rearrange the equation:
\[
w = \frac{V}{l \times h}
\]
Now, substituting the values for \( V \), \( l \), and \( h \):
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
Thus, the rearranged formula for \( w \) becomes:
\[
w = \frac{60}{4 \times 5}
\]
This means:
\[
w = \frac{60}{20} = 3
\]
So, the width \( w \) is 3 ft.
In summary, the formula rearranged for \( w \) is:
\[
w = \frac{V}{l \times h}
\]
This can be presented as:
\[
w = \frac{60}{4 \times 5}
\]
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