Asked by CC

Calculate the molality of methanol in a solution prepared by dissolving 75.0 mL of methanol, CH3OH (d = 0.791 g/mL), in 150 g of ethanol, C2H5OH.
Answered by DrBob222
The definition is M = mols/kg solvent
Answered by Fai
My calculation
0.791g/ml x 75ml /46 g/mol = 1.29M
1.29M /0.15KG
x= 0.116M
Answered by DrMeir
75mL*.791g/mL= 59.325g

59.325g/32g/mol=1.854moles

1.854moles/.150kg=12.36m
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