Asked by Amy
A car drove off a cliff. The cliff was 8 ft high and the car landed 45 ft away from the edge of the cliff. What was the speed when the car left the cliff?
Answers
Answered by
bobpursley
How much time does it take to fall 8 feet?
h=1/2 g t^2
8=1/2 32 t^2
t^2=1/2
t= .707 sec
distance= Vi*.707=45
vi= 45*sqrt2 ft/sec
h=1/2 g t^2
8=1/2 32 t^2
t^2=1/2
t= .707 sec
distance= Vi*.707=45
vi= 45*sqrt2 ft/sec
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